2(3x-1)²-32=0 27(1-4x)³=125 Find the value of X

2(3x-1)²-32=0 27(1-4x)³=125 Find the value of X

2 (3x-1) & sup2; - 32 = 0 2 (3x-1) & sup2; = 32 (3x-1) & sup2; = 163x-1 = ± 43x = 5 or - 33x = 5 x = 5 / 33x = - 3 x = - 127 (1-4x) & sup3; = 125 (1-4x) & sup3; = 125 / 271-4x = 5 / 34x = 1-5 / 34x = - 2 / 3x = - 1 / 6