Subtract 1 / 2 of 2007, then subtract the remaining 1 / 3, then subtract the remaining 1 / 4... And so on until you subtract the remaining 1 / 2007 Second, we know that a + B + C = 0, and a + B + C = 0 Third: if the square of | X-1 | + | y + 2 | + (Z-3), find the value of formula (x + 1) (Y-2) (Z-3)

Subtract 1 / 2 of 2007, then subtract the remaining 1 / 3, then subtract the remaining 1 / 4... And so on until you subtract the remaining 1 / 2007 Second, we know that a + B + C = 0, and a + B + C = 0 Third: if the square of | X-1 | + | y + 2 | + (Z-3), find the value of formula (x + 1) (Y-2) (Z-3)

2007(1-1/2)(1-1/3)(1-1/4)...(1-/2007)
=2007*1/2*2/3*3/4...*2006/2007
=1
The second way
D: The square of a, the square of B, the square of C > = 0
A supplementary question: the square of | X-1 | + | y + 2 | + (Z-3) = 0
x=1,y=-2,z=3
（x+1)(y-2)(z-3）=2*(-4)*0=0