Find the equations of the following circles and draw the figure. The center of the circle is point C (8, - 3), and the main drawing is through point a (5,1) 2, a (- 1,5), B (5,5) C (6, - 2)

Find the equations of the following circles and draw the figure. The center of the circle is point C (8, - 3), and the main drawing is through point a (5,1) 2, a (- 1,5), B (5,5) C (6, - 2)

The distance between these two points is the radius R ^ 2 = (8-5) ^ 2 + (- 3-1) ^ 2 = 9 + 16 = 25R = 5, so the circle equation is (X-8) ^ 2 + (y + 3) ^ 2 = 25, with (8, - 3) as the center and 5 as the radius. Let the circle equation be x ^ 2 + y ^ 2 + DX + ey + F = 0, because the circle passes three points a (- 1,5), B (5,5), C (6, - 2), so 1 + 25-d + 5E + F = 025 + 25 +