Given that the even function f (x) decreases monotonically on [2,4], then the relation between the magnitude of F (8 of Log1 / 2) and f (- π) is

Given that the even function f (x) decreases monotonically on [2,4], then the relation between the magnitude of F (8 of Log1 / 2) and f (- π) is

Since the function is even, f (x) increases monotonically on [- 4, - 2]
8 = - 3 > - π of Log1 / 2
So f (- 3) > F (- π)
So f (8 of Log1 / 2) > F (- π)