In the equation y = ax square + BX + C, when x = 0, y = 3, when x = 1 or x = - 3, y = 0, then what are a, B, C equal to

In the equation y = ax square + BX + C, when x = 0, y = 3, when x = 1 or x = - 3, y = 0, then what are a, B, C equal to

Y = the square of AX + BX + C, when x = 0, y = 3, when x = 1 or x = - 3, y = 0
Then 3 = C
0=a+b+c
0=9a-3b+c
The solution is a = - 1, B = - 2, C = 3

Elden Ring Premiere

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