The polynomial X & sup2; - (M + 1) x + M can be divisible by X + 1 to find the value of M

The polynomial X & sup2; - (M + 1) x + M can be divisible by X + 1 to find the value of M

If there is a factor X + 1 in the polynomial, then when x = - 1, x + 1 = 0
In this case, the value of the polynomial must be 0
So substitute x = - 1 to X & sup2; - (M + 1) x + M
1+(M+1)+M=0
2M+2=0
M=-1