What is the positional relationship between the line L: 3x + 4Y + 12 = 0 and (x-1) ^ 2 + (y + 1) ^ 2 = 9?

What is the positional relationship between the line L: 3x + 4Y + 12 = 0 and (x-1) ^ 2 + (y + 1) ^ 2 = 9?

Analysis: 3x + 4Y + 12 = 0 is a straight line; (x-1) ^ 2 + (y + 1) ^ 2 = 9 is a circle with (1, - 1) as the center and 3 as the radius; this is the problem of the position relationship between the line and the circle. Just compare the relationship between the distance d from the center of the circle to the straight line and the radius R. the distance d from the center of the circle to the straight line = (| 3 * 1 + 4 * (- 1) + 12 |) / under the root sign (3 ^