No matter what the value of M is, the image of quadratic function y = x ^ 2 - (2-m) x + m always passes through the point? Why (1 + x) M = Y-X ^ 2 + 2x find out this step and then how to do it?

No matter what the value of M is, the image of quadratic function y = x ^ 2 - (2-m) x + m always passes through the point? Why (1 + x) M = Y-X ^ 2 + 2x find out this step and then how to do it?

y=x^2-(2-m)x+m
It is concluded that: (1 + x) M = Y-X ^ 2 + 2x
No matter what the value of M is, the image of quadratic function y = x ^ 2 - (2-m) x + m always passes through a point. For the equation (1 + x) M = Y-X ^ 2 + 2x, M has infinite solution
Namely:
1+x=0,y-x^2+2x=0;
The solution is: x = - 1, y = 3