Please refer to the following example to solve the equation 2x-lx-1l-1 = 0. Example: solve the equation 2x-lxl-2 = 0 (1) when x is greater than or equal to 0, The original equation can be reduced to 2x-x-2 = 0, and the solution is x = 2 (2) When x < 0, the original equation can be reduced to 2x + X-2 = 0, and the solution is x = 2 / 3 Because x < 0, so x = 2 / 3 does not meet the conditions, rounding off, so the solution of the original equation is x = 2

Please refer to the following example to solve the equation 2x-lx-1l-1 = 0. Example: solve the equation 2x-lxl-2 = 0 (1) when x is greater than or equal to 0, The original equation can be reduced to 2x-x-2 = 0, and the solution is x = 2 (2) When x < 0, the original equation can be reduced to 2x + X-2 = 0, and the solution is x = 2 / 3 Because x < 0, so x = 2 / 3 does not meet the conditions, rounding off, so the solution of the original equation is x = 2

1) When X-1 ≥ 0 inch, that is, X ≥ 1. The original equation is 2x-x 1-1 = 0, and the solution is x = 0 (rounding off) 2. When x < 1, the original equation is 2x-1 X-1 = 0, and the solution is x = 2 / 3