If the quadratic power of (x-5y-16) + |5y-5x-4 | = 0, then x = (), y = ()

If the quadratic power of (x-5y-16) + |5y-5x-4 | = 0, then x = (), y = ()

That is x-5y-16 = 0
5y-5x-4=0
The solution is x = - 5, y = - 21 / 5