The known function f (x) = x-4x + A + 3, G (x) = MX + 5-2m 1: If y = f (x) has zero point on [- 1,1}, find the value range of real number a 2: When a = 2, if any x 1 belongs to [1,3], there is always x 2 belonging to [1,4], if f (x 1) = g (x 2) holds, then the value range of real number m is obtained

The known function f (x) = x-4x + A + 3, G (x) = MX + 5-2m 1: If y = f (x) has zero point on [- 1,1}, find the value range of real number a 2: When a = 2, if any x 1 belongs to [1,3], there is always x 2 belonging to [1,4], if f (x 1) = g (x 2) holds, then the value range of real number m is obtained

solution
1. F (x) = x ^ 2-4x + A + 3, the axis of symmetry is x = 2,
In order to make it have zero point on [- 1,1],
must:
△=16-4(a+3)>0
f(1)=1-4+a+3=0
The solution is - 8

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