The linear equation of the line 3x + 5y-1 = 0 is symmetric with respect to the line 4x + 3y-5 = 0

The linear equation of the line 3x + 5y-1 = 0 is symmetric with respect to the line 4x + 3y-5 = 0

L1:3x+5y-1=0.(1)L2:4x+3y-5=0.(2)k(L1)=-3/5,k(L2)=-4/3[k(L1)-k(L2)]/[1+k(L1)*k(L2)]=[k(L2)-k]/[1+k*k(L2)][-3/5-(-4/3)]/[1+(-3/5)*(-4/3)]=[(-4/3)-k]/[1+k*(-4/3)]k=-35*(2)-3*(1):x=2,y=-1L:y+1=-3*(x-2)3x+...