Given that the lines L1: y = AX-2 and L2: y = (2a + 1) x + 1 are perpendicular to each other, then a is equal to? None Given that the lines L1: y = AX-2 and L2: y = (2a + 1) x + 1 are perpendicular to each other, then a is equal to? No solution, so that a is equal to - 1 or 1 / 2

Given that the lines L1: y = AX-2 and L2: y = (2a + 1) x + 1 are perpendicular to each other, then a is equal to? None Given that the lines L1: y = AX-2 and L2: y = (2a + 1) x + 1 are perpendicular to each other, then a is equal to? No solution, so that a is equal to - 1 or 1 / 2

The lines L1: y = AX-2 and L2: y = (2a + 1) x + 1 are perpendicular to each other
So the slope product is - 1
That is, a (2a + 1) = - 1
That is 2A ^ 2 + A + 1 = 0
Δ=1-8