The distance between two parallel lines L1: 3x + 4Y + 2 = 0, L2: 6x + 8y-4 = 0 is ()

The distance between two parallel lines L1: 3x + 4Y + 2 = 0, L2: 6x + 8y-4 = 0 is ()

L2: 6x + 8y-4 = 0 becomes L2: 3x + 4Y-2 = 0
The absolute value of the distance d = 2 - (- 2) divided by the square of 3 under the root plus the square of 4 = 4 / 5