It is known that Y1 = 2 (3x + 4) and y2 = 5 (2x-7). When we find out the value of X, Y1 is 3

It is known that Y1 = 2 (3x + 4) and y2 = 5 (2x-7). When we find out the value of X, Y1 is 3

From the title,
y1-y2=3,
That is, 2 (3x + 4) - 5 (2x-7) = 3
6x+8-10x+35=3
-4x=-40
x=10
When x = 10, Y1 is 3 times larger than Y2