Given that Y1 = 2 (3x + 4), y2 = 5 (2x-7), when x is what value, Y1 is 3 times larger than Y2

Given that Y1 = 2 (3x + 4), y2 = 5 (2x-7), when x is what value, Y1 is 3 times larger than Y2

Y1 is 3 larger than Y2, that is, Y1 = Y2 + 3
y1=2(3x+4),y2=5(2x-7),
2(3x+4)=5(2x-7)+3
6x+8=10x-35+3
8+35-3=(10-6)x
40=4x
x=10
So, when x is 10, Y1 is 3