It is known that: Y1 = 2 (3x + 4), y2 = 5 (2x-8) when x takes what value, (1) Y1 and Y2 are opposite to each other? (2) y 2 smaller than Y2?

It is known that: Y1 = 2 (3x + 4), y2 = 5 (2x-8) when x takes what value, (1) Y1 and Y2 are opposite to each other? (2) y 2 smaller than Y2?

(1) And are opposite to each other, and the two numbers are added to get 0
2(3x+4)+5(2x-8)=0
16x-32=0
x=2
When x = 2, Y1 and Y2 are opposite to each other;
(2)、y2-y1=2
[5(2x-8)]-[2(3x+4)]=2
4x-48=2
x=12.5