The solution set of equation log3 (x ^ 2-3x + 1) = 1 is a, equation The solution set of equation log3 (x ^ 2-3x + 1) = 1 is a, the solution set of equation 9 ^ x-4 * 3 ^ (x + 1) + 27 = 0 is B, then the relationship between a and B is A.M=N B. N is contained in M C. M is contained in n D. M ∩ n = nonempty set

The solution set of equation log3 (x ^ 2-3x + 1) = 1 is a, equation The solution set of equation log3 (x ^ 2-3x + 1) = 1 is a, the solution set of equation 9 ^ x-4 * 3 ^ (x + 1) + 27 = 0 is B, then the relationship between a and B is A.M=N B. N is contained in M C. M is contained in n D. M ∩ n = nonempty set

There is no answer to this question!
The former equation solution set is: X1 = (3 + sqrt (17)) / 2., X2 = (3-sqrt (17)) / 2, while the latter equation solution set is: X3 = 1, X4 = 2
So the two solutions are two points, and are different, there is no intersection to speak of, can only be empty set!
I don't know what you think? Is it the same as what I think?