In the acute triangle ABC, the lengths of three sides a, B and C are all integers, and a

In the acute triangle ABC, the lengths of three sides a, B and C are all integers, and a

∵ B + C > A, that is 20-a > a
∴a＜10
And ∵ a, B, C are all integers and a > b > C, a + B + C = 20
There are four cases: ① a = 9, B = 8, C = 3, ② a = 9, B = 7, C = 4,
③a＝9,b＝6,c＝5 ④a＝8,b＝7,c＝5.
And ∵ is an acute triangle, that is, B + C > a
∴a＝8,b＝7,c＝5.
Using cosine theorem, COSC = (a + B-C) △ 2Ab = 11 / 14

Elden Ring Premiere

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