The three sides a, B, C of the unequal triangle ABC are integers and a & sup2; + B & sup2; - 3a-4b + 13 = 0 to find the value of C a²+b²-6a-4b+13=0 a²-6a+9+b²-4b+4=0 (a-3)²+(b-2)²=0 a=3,b=2 Because the perfect square is nonnegative a-b=1,a+b=5 one

The three sides a, B, C of the unequal triangle ABC are integers and a & sup2; + B & sup2; - 3a-4b + 13 = 0 to find the value of C a²+b²-6a-4b+13=0 a²-6a+9+b²-4b+4=0 (a-3)²+(b-2)²=0 a=3,b=2 Because the perfect square is nonnegative a-b=1,a+b=5 one

9 and 4 are two constants separated from 13, thus forming two complete square formulas (A & # 178; - 6A + 9) (B & # 178; - 4B + 4), thus (A-3) &# 178; + (b-2) &# 178; = 0