Take a random number from the integers of 1-2000. What's the probability that the integers can't be divided by 6 or 8 Because 333 is less than 2000 / 6 and less than 334, P (a) = 333 / 2000! Why should p (a) be expressed in this way and 333 / 2000?

Take a random number from the integers of 1-2000. What's the probability that the integers can't be divided by 6 or 8 Because 333 is less than 2000 / 6 and less than 334, P (a) = 333 / 2000! Why should p (a) be expressed in this way and 333 / 2000?

This means that there are 333 integers that can be divided into 6 integers, and the probability is 333 / 2000

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