A student forgot to multiply 1 by the least common multiple 12 of each denominator when solving the equation 10-x of 4 / 4 = x-m of 1-3. The result is x = - 1. Please help him find the correct solution of the equation

A student forgot to multiply 1 by the least common multiple 12 of each denominator when solving the equation 10-x of 4 / 4 = x-m of 1-3. The result is x = - 1. Please help him find the correct solution of the equation

(10-x) / 4 = 1 - (x-m) / 3 the case of miscalculation is 3 (10-x) = 1-4 (x-m). At this time, x = - 1, that is, 3 * (10 + 1) = 1-4 (- 1-m) 33 = 1 + 4 + 4m4m = 28m = 7. Therefore, the original equation is (10-x) / 4 = 1 - (X-7) / 33 (10-x) = 12-4 (X-7) 30-3x = 12-4x + 284x-3x = 40-30x = 10 * this is a multiplier sign