We know that a is a real number, a = a ^ 2 / (a ^ 4 + 1), B = a ^ 4 / (a ^ 6 + 1), compare the size of a and B I hope it can be explained more clearly

We know that a is a real number, a = a ^ 2 / (a ^ 4 + 1), B = a ^ 4 / (a ^ 6 + 1), compare the size of a and B I hope it can be explained more clearly

Look at the value of a-b
A-B
=a^2/(a^4+1)-a^4/(a^6+1)
=[a^2(a^6+1)-a^4(a^4+1)]/[(a^4+1)(a^6+1)]
=(a^8+a^2-a^8-a^4)/[(a^4+1)(a^6+1)]
=-a^2(a^2-1)/[(a^4+1)(a^6+1)]
When a = 0 or a = 1 or a = - 1, A-B = 0 and a = B
0

Elden Ring Premiere

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