11 (2) if real numbers x and y satisfy: X / (2 ^ 10 + 5 ^ 3) + Y / (2 ^ 10 + 6 ^ 3) = 1, X / (3 ^ 10 + 5 ^ 3) + Y / (3 ^ 10 + 6 ^ 3) = 1, then x + y= Let 2 ^ 10 and 3 ^ 10 be two real roots of the equation x / (T + 5 ^ 3) + Y / (T + 6 ^ 3) = 1 about t The equation x / (T + 5 ^ 3) + Y / (T + 6 ^ 3) = 1 can be obtained It is reduced to the general form of quadratic equation t^2+(5^3+6^3-x-y)t+…… =0 (the part of the ellipsis doesn't matter) According to the relationship between root and coefficient 2^10+3^10=x+y-5^3-6^3 So x + y = 2 ^ 10 + 3 ^ 10 + 5 ^ 3 + 6 ^ 3 my question is: "x + y = 2 ^ 10 + 3 ^ 10 + 5 ^ 3 + 6 ^ 3" this is the result? How many numbers does it equal? Do you want to calculate it hard?

11 (2) if real numbers x and y satisfy: X / (2 ^ 10 + 5 ^ 3) + Y / (2 ^ 10 + 6 ^ 3) = 1, X / (3 ^ 10 + 5 ^ 3) + Y / (3 ^ 10 + 6 ^ 3) = 1, then x + y= Let 2 ^ 10 and 3 ^ 10 be two real roots of the equation x / (T + 5 ^ 3) + Y / (T + 6 ^ 3) = 1 about t The equation x / (T + 5 ^ 3) + Y / (T + 6 ^ 3) = 1 can be obtained It is reduced to the general form of quadratic equation t^2+(5^3+6^3-x-y)t+…… =0 (the part of the ellipsis doesn't matter) According to the relationship between root and coefficient 2^10+3^10=x+y-5^3-6^3 So x + y = 2 ^ 10 + 3 ^ 10 + 5 ^ 3 + 6 ^ 3 my question is: "x + y = 2 ^ 10 + 3 ^ 10 + 5 ^ 3 + 6 ^ 3" this is the result? How many numbers does it equal? Do you want to calculate it hard?

No more calculation, this is the final result, if you really want the result, you can use the calculator