Given the function f (x) = {x2 + 1, (x is greater than or equal to 0), - 2x (x)
Piecewise function, when x = 0, f (x) = x ^ 2 + 1 = 10, then x2 = 3
So f (x) = 10, the corresponding solution is X1 = - 5, X2 = 3
Piecewise function, when x = 0, f (x) = x ^ 2 + 1 = 10, then x2 = 3
So f (x) = 10, the corresponding solution is X1 = - 5, X2 = 3