Given the circle x square + y square + 25 = 0, find the tangent equation of the point (4, - 3)

Given the circle x square + y square + 25 = 0, find the tangent equation of the point (4, - 3)

The circular equation is reduced to (x plus minus a) square + (y plus minus b) square = 0
Get the coordinates of the center of the circle. Find the tangent line from (4. - 3) to the circle. Take two points in. There are two tangents. I can work out with you. But I'd better work it out myself. It's more specific than what the man said. I can't understand what he said--#