F (log2x) = X-1 / X to find f (x) It's the logarithm of X with base 2

F (log2x) = X-1 / X to find f (x) It's the logarithm of X with base 2

Let a = log2 (x)
Then x = 2 ^ A
So f (a) = 2 ^ A-1 / 2 ^ a
So f (x) = 2 ^ X-1 / 2 ^ X