It is known that the function y = f (x) is an odd function. When x > 0, f (x) = log2x, then the value of F (f (1 / 16)) is equal to?

It is known that the function y = f (x) is an odd function. When x > 0, f (x) = log2x, then the value of F (f (1 / 16)) is equal to?

f(f(1/16))
=f(log2(1/16)
=f(-4)
=-f(4)
=-log2(4)
=-2