When Xiao Ming solved the equation 2x-15 + 1 = x + a 2, due to carelessness, the left 1 of the equation was not multiplied by 10 when the denominator was removed, so the solution obtained was x = 4 When Xiao Ming solved the equation 2x-15 + 1 = x + A2, due to carelessness, when the denominator is removed, the left 1 of the equation is not multiplied by 10, so the solution obtained is x = 4. Try to find the value of a and correctly find the solution of the equation

When Xiao Ming solved the equation 2x-15 + 1 = x + a 2, due to carelessness, the left 1 of the equation was not multiplied by 10 when the denominator was removed, so the solution obtained was x = 4 When Xiao Ming solved the equation 2x-15 + 1 = x + A2, due to carelessness, when the denominator is removed, the left 1 of the equation is not multiplied by 10, so the solution obtained is x = 4. Try to find the value of a and correctly find the solution of the equation

（2x-1)/5+1=(x+a)/2
2 (2x-1)+1=5(x+a)
4x-2+1=5x+5a
-1-5a=x
-1-5a=4
a=-1
The solution of the correct equation
2x-1)/5+1=(x+a)/2
2 (2x-1)+10=5(x-1)
4x-2+10=5x-5
x=13