Find 1 / 100 + 1 / 101 + 1 / 102 + +Integral part of 1 / 300 Can this question be written like this? (1/100+1/300)*201÷2=67/50=1.34 The result is 1

Find 1 / 100 + 1 / 101 + 1 / 102 + +Integral part of 1 / 300 Can this question be written like this? (1/100+1/300)*201÷2=67/50=1.34 The result is 1

No, it's easy to get the range of the original formula by using the method of scaling (try it yourself), and the integer part of all numbers in this range is 1, so the result is 1