Successive difference formula Using the puncher to make the paper tape, there are ABCDEFG... Points. Let the distances of ab.bc.cd.de.ef.fg... In the paper tape be s1.s2.s3.s4.s5.s6 respectively, The time interval corresponding to two adjacent points is t. the velocity of the object at point a is va. according to the uniform velocity linear motion formula and the velocity formula, it is proved that the displacement difference of the object passing through in the continuous and equal time interval is a constant, and satisfies s2-s1 = 3-s2 = s4-s3 =... = at ＾ 2; The proof process is as follows (hint: s1.s2 is calculated by displacement formula first) It's at ^ 2

Successive difference formula Using the puncher to make the paper tape, there are ABCDEFG... Points. Let the distances of ab.bc.cd.de.ef.fg... In the paper tape be s1.s2.s3.s4.s5.s6 respectively, The time interval corresponding to two adjacent points is t. the velocity of the object at point a is va. according to the uniform velocity linear motion formula and the velocity formula, it is proved that the displacement difference of the object passing through in the continuous and equal time interval is a constant, and satisfies s2-s1 = 3-s2 = s4-s3 =... = at ＾ 2; The proof process is as follows (hint: s1.s2 is calculated by displacement formula first) It's at ^ 2

Is it equal to a * T ^ 2? Are you sure it's not (1 / 2) * a * T ^ 2?
This is to prove that when the acceleration is constant, the distance of acceleration is certain in the same time
Displacement = initial velocity * time + 0.5 * acceleration * time square. For convenience, you can just calculate from the best shape, such as S2, which is the displacement in two seconds minus that in one second