When half of the aluminum block with a volume of 100 cubic centimeter (aluminum density = 2.7x10 cubic kg / M) is immersed in water, its buoyancy is___ N, The buoyancy it gets when it's immersed in alcohol___ N. (density of alcohol = 0.8x10 to the third power kg / M) The same ball can float on the liquid surface when it is placed in water or kerosene respectively. The buoyancy received by the ball in water is less than that received by the water___ Buoyancy in kerosene, the volume of the ball in water___ The volume of a ball immersed in kerosene

When half of the aluminum block with a volume of 100 cubic centimeter (aluminum density = 2.7x10 cubic kg / M) is immersed in water, its buoyancy is___ N, The buoyancy it gets when it's immersed in alcohol___ N. (density of alcohol = 0.8x10 to the third power kg / M) The same ball can float on the liquid surface when it is placed in water or kerosene respectively. The buoyancy received by the ball in water is less than that received by the water___ Buoyancy in kerosene, the volume of the ball in water___ The volume of a ball immersed in kerosene

1. Row v = 100 cubic centimeter / 2 = 50 cubic centimeter = 5 * 10 minus 5 power
F floating = P liquid V row g = 0.8 * 10 third power kg / m3 * 5 * 10 negative fifth power m3 * 10N / kg = 0.4N
So fill in "0.4" in the first blank
2. Because the density of water is greater than that of kerosene, the second empty filling is "greater than" according to f floating = P liquid V row G
3. Because the density of water is higher than that of kerosene, the volume immersed in water is smaller than that in kerosene
Please accept

What is the buoyancy of an object with a weight of 0.98n and a density of 0.8 times the third power of 10 when it is put into water? What is the buoyancy of the object immersed in water

Because the density is less than water, the object floats, f = g = 0.98n
The volume of immersion is the volume of boiled water, that is, the weight of boiled water is equal to the weight of the object
V = 0.98 / (9.8 * 1.0) = 0.1 cubic centimeter

If the gravity of the cylinder is 12n and the buoyancy is 8N, what is the density of the cylinder?

Because the gravity of the cylinder is 12n, g = P, GV = 12n (1)
Because the buoyancy is 8N, f floating = P water GV row = 8N (2)
Because it's submerged in water, so v = V row
(1) (2) = P column / P water = 1.5
Because pwater = 1g / cm3
So p column = 1.5g/cm3

The displacement of Wuhan is 7000t, the density of sea water is 1.03 × 10 cubic kg / m3, and the buoyancy of Wuhan is calculated by taking ten Niu as G

You see, since Wuhan is a ship, it must be floating in the water, then its force is f = mg = 7000 * 10 ^ 3 * 10 = 7 * 10 ^ 7n. If the object floats on the water, then its buoyancy is equal to its gravity