A question about the absolute value of junior high school mathematics |x+2|-|x-3|

A question about the absolute value of junior high school mathematics |x+2|-|x-3|

1: When x > 3, the equation is 5
2: When - 2

The correct one in the following statement is ()
A. There are three numbers whose absolute value is less than 2
B. There are two numbers whose absolute value is two
C. There is one number whose absolute value is - 2
D. The absolute value of any number is positive
|Can x | x = x and | x | x = - x hold at the same time____
When a > 0, |a | =____
When a = 0, |a | =____
When a

The correct one in the following statement is (AB)
A. There are three numbers whose absolute value is less than 2
B. There are two numbers whose absolute value is two
C. There is one number whose absolute value is - 2
D. The absolute value of any number is positive
Can x | x = x and | x | x = - x hold at the same time__ 0__
When a > 0, |a | =_ Positive number___
When a = 0, |a | =_ 0___
When a

On the absolute value of junior high school mathematics
If a, B and C are all rational numbers that are not zero, the absolute value of a is divided into a, plus the absolute value of B is divided into B, plus the absolute value of C is divided into C. evaluate. (the question seems to be this, I don't remember it very much. This is a question we have in our exam. Do we have four solutions? Positive and negative 3 and positive and negative 1)

Yes
1. When one of a, B and C is greater than (two are less than) 0, the value is (- 1)
2. When two of a, B and C are greater than (one is less than) 0, the value is (1)
3. When a, B and C are all greater than 0, the value is (3)
4. When a, B and C are all less than 0, the value is (- 3)
Discuss together

1. A + B-C > 0, A-B + C > 0, - A + B + C > 0, how to know if a, B, C are all greater than 0?
2. If (A-1 / 3) square > 0, then a

Add a + B-C > 0 and A-B + C > 0 to get 2A > 0, that is, a > 0
Similarly, b > 0, C > 0
It is wrong to get A-1 / 3 > 0 or A-1 / 31 / 3 or A-1 / 31 / 3 from (A-1 / 3) square > 0