How to calculate 3x-5xy + 3Y / (- x + 3xy-y)?

How to calculate 3x-5xy + 3Y / (- x + 3xy-y)?

3x-5xy+3y/(-x+3xy-y)
=(3x-5xy)*(-x+3xy-y)/(-x+3xy-y)+3y/(-x+3xy-y)
=[(3x-5xy)*(-x+3xy-y)+3y]/(-x+3xy-y)
=3*x-11*x*y+2*y+15*x*y^2-5*y^2-3/x*y

There are two numbers whose absolute value is equal to a positive number

One is a negative number, the other is a positive number. For example:! - 5! = 5! 5! = 5, the absolute value of any number is a positive number

The number whose absolute value is equal to itself is______ ．

A number whose absolute value equals itself is nonnegative

The absolute value is equal to its own number, there are positive numbers and 0, then the absolute value is equal to its opposite number? If so, what number is it?
Negative numbers and zero,

Non positive number