If a 2A + 2 3A + 3... Is an equal ratio sequence, then a + 2 =

If a 2A + 2 3A + 3... Is an equal ratio sequence, then a + 2 =

(2a+2)(2a+2)=a(3a+3)
The solution is a = - 1 or a = - 4 because a = - 1 makes 2A + 2 zero
So a = - 4, a + 2 = - 2

2A times 3A equals
How much is it
Why square

6a^2

What is 300 + 3a-200 + 2A

300+3a-200+2a
=300-200+3a+2a
=100+5a

Given (a + 2) & sup2; + A + B + 5 = 0, find the value of 3A & sup2; B - [2A & sup2; B - (2ab-a & sup2; b) - 4A & sup2;] - ab
Give high marks for the answers

(a + 2) & sup2; + A + B + 5 = 0, (a + 2) & sup2; = 0, a + B + 5 = 0A = - 2, B - 2 + B + 5 = 0, B + 3 = 0b = - 33A & sup2; B - [2A & sup2; B - (2ab-a & sup2; b) - 4A & sup2;] - AB = 3A & sup2; B - [2A & sup2; b-2ab + A & sup2; b-4a & sup2;] - AB = 3A & sup2; B - [3A & sup2; B -

Mathematics problem 3A - & sup2; B × 2Ab - & sup2;

3a－2b×2ab－2
=3b/a2×2a/b2=6/ab

Let a and B satisfy (a + b) 2 = 1 and (a-b) 2 = 25, then A2 + B2 + ab=______ ．

∵ (a + b) 2 = 1, (a-b) 2 = 25, ∵ A2 + B2 + 2Ab = 1, A2 + b2-2ab = 25, ②, ① + ②: A2 + B2 = 13, ① - ②: ab = - 6, ∵ A2 + B2 + AB = 13-6 = 7

Given that real numbers a and B satisfy (a + b) & sup2; = 7 (a-b) & sup2; = 2, find the value of a & sup2; + B & sup2; + ab

From (a + b) ² = 7, we get a ^ 2 + B ^ 2 + 2Ab = 7, from (a-b) ² = 2, we get a ^ 2 + B ^ 2-2ab = 2, subtracting the two formulas, we get 4AB = 5, namely AB = 5 / 4, adding the two formulas, we get 2 (a ^ 2 + B ^ 2) = 9, namely a ^ 2 + B ^ 2 = 9 / 2, so a & #178; + B & #178; + AB = 9 / 2 + 5 / 4 = 23 / 4

For all non-zero real numbers, if a + B = AB, then what is the value of 1 / A & sup2; + 2 / AB + 1 / B & sup2

Hello, zld122. The answer to vcylulin is right, but there is a problem with the method,
1/a^2+2/ab+1/b^2=(1/a+1/b)^2
It can be obtained by dividing in brackets
The original formula = [(B + a) / AB] ^ 2 and because a + B = AB, the original formula = 1

If real numbers a and B satisfy | A-B | + (1 / 2a-1) ^ 2 = 0, find the value of 1 + ab

∵|a-b|≥0 （1/2a-1)^2≥0
And | A-B | + (1 / 2a-1) ^ 2 = 0
∴|a-b|=0 ,（1/2a-1)^2=0
a-b=0,1/2a-1=0
The solution is a = 2, B = 2
That is, 1 + AB = 1 + 4 = 5

X & sup2; + X-1 = 0, find the value of 2 times the cubic power of X + 2x & sup2; - 2x + 2_

X²＋X-1＝0
x²+x=1
2 times the cubic power of X + 2x & sup2; - 2x + 2
=2x（x²+x）-2x+2
=2x×1-2x+2
=0+2
=2