1. X & sup2; + 2 () + 1 / 16 = (x + 1 / 4) & sup2; 2.4a & sup2; + 12ab + () = (2a +) & sup2;

1. X & sup2; + 2 () + 1 / 16 = (x + 1 / 4) & sup2; 2.4a & sup2; + 12ab + () = (2a +) & sup2;

1. X & sup2; + 2 (x of 4) + 1 of 16 = (x + 1 of 4) & sup2;
2.4a²+12ab+（9b² ）=（2a+3b ）²

About 4a-a ^ 2-4 / 4-A ^ 2

=-（a^2-4a+4)/-（a^2-4)
=-(a-2)^2/-(a-2)(a+2)
=(a-2)/(a+2)
Add points appropriately

When we simplify a fraction, we use 2 about twice and 3 about once. The result is 56. The original fraction is 56______ ．

5 × 2 × 2 × 36 × 2 × 2 × 3 = 6072

If you divide a score by two and then 3, you get 2 / 7. What's the original score?

We use 2 twice and then 3 once. We can see that the numerator and denominator are divided by 2 * 2 * 3 = 12 at the same time, so the original fraction is 2 * 12 / (7 * 12) = 24 / 84

If a = 3, B = 2 and a / b = A / B, find the value of 3a-2b

Are you sure?

If AB is not equal to 0, find all the values of 3A / | a | + | B | / 2B

The discussion is divided into four situations
1 a0

A + B = 2 ab = 3 find the value of 2 [AB + (- 3a)] - 3 (2B AB)
Such as the title

Original formula = 2ab-6a-6b + 3AB
=5ab-6(a+b)
When a + B = 2, ab = 3
Original formula = 5 * 3-6 * 2
=15-12
=3

If a ^ 2 + 2B = 3 5A ^ 2 + 10B = () - A ^ 2-2b = () - 3A ^ 2-6b = () if B / a = 3 4B / 3A = () a / 6B = ()
If x ^ 2 + x = 1
3x^2+3x 3x^2+3x-5
If a + B / A-B = 3
(a+b)/(a-b)-[4(a-b)]/(a+b)
If x + 2Y ^ 2 + 5 = 7
3x+6y^2+4

Calculate (3a + 2b) (6a-5b) (2b-3a) (5b + 6a) 10.1 times 9.9 = how many squares - how many squares

Answer: the original formula = (2B + 3a) (2b-3a) (6a + 5b) (6a-25b2) = - 324a4-100b4 + 369a2b2 (the number after the letter is the power)

To solve the equations 3x-2z = 1 4x + 2Y + Z = 0 2Y + 5Z = 4

First, multiply the two equations by 2, and then add them to each other to get: 11x + 4Y = 1
Then multiply formula 2 by 5 and subtract formula 3 to get: 20x + 8y = - 4
If we multiply the two formulas by two and subtract the two formulas, we can get the solution x = 3
Substituting, y = - 8, z = 4