It is known that the absolute value of a is equal to 3, the absolute value of B is equal to 1, the opposite number of C is 5, and the absolute value of a + B is equal to a plus B. to find the value of a minus B plus C, ask the great God for help

It is known that the absolute value of a is equal to 3, the absolute value of B is equal to 1, the opposite number of C is 5, and the absolute value of a + B is equal to a plus B. to find the value of a minus B plus C, ask the great God for help

-C = 5, C = - 5 | a + B | = a + B indicates that a + b > 0 | a | = 3 | B | = 1 | a = 3, B = ± 1. ① when B = 1, the original formula = 3-1 + (- 5) = - 3. ② when B = - 1, the original formula = 3 - (- 1) + (- 5) = - 1

|X + 1 | + | x-3 | > 5 this kind of inequality with absolute value how to solve? Ask for the help of God
Supplement: the original inequality is equivalent to: X ＜ - 1 or - 1 ≤ x ≤ 3 or X ＞ 3 - x-1-x + 3 ＞ 5 x + 1-x + 3 ＞ 5 x + 1 + x-3 ＞ 5. From the above, we can get x ＜ - 3 / 2 or X ＞ 7 / 2. Although I have found the solution to this problem, why is it divided into "X"

The absolute value of the formula is equal to 0 to discuss the classification between partitions, take off the absolute value symbol is easy to do