Given a = - 3, B = - (+ 4), C = - (- 1), d = | - 2 |, find the value of ab-bc + cd-d

Given a = - 3, B = - (+ 4), C = - (- 1), d = | - 2 |, find the value of ab-bc + cd-d

b=-（+4）=-4，c=-（-1）=1，d=|-2|=2，ab-bc+cd-d=-3×（-4）-（-4）×1+1×2-2=12+4+2-2=16．

Given the absolute value of a = - 3, B = - (+ 4), C = - (- 1), d = negative 2, find the value of ab-bc + cd-d

Solution
Because a = - 3, B = - (+ 4), C = - (- 1), d = the absolute value of negative 2
therefore
a=-3
b=-4
c=1
d=2
therefore
ab-bc+cd-d=12+4+2-2=16

Given a = - 3, B = - (+ 4), C = - (- 1), d = | - 2 |, find the value of ab-bc + cd-d

b=-（+4）=-4，c=-（-1）=1，d=|-2|=2，ab-bc+cd-d=-3×（-4）-（-4）×1+1×2-2=12+4+2-2=16．