What happens to the image of the linear function y = ax + B and y = AX2 + BX + C in the same direct coordinate system

What happens to the image of the linear function y = ax + B and y = AX2 + BX + C in the same direct coordinate system

Because AB is not equal to 0, a is not equal to 0 and B is not equal to 0
If A0, then y = ax ^ 2 + BX + C opens up, and y = ax + B goes through quadrant one, two, and three

It is known that n is an integer and the intersection point of the first-order function y = ½ X + N and y = 2x + 7-N is in the second quadrant. The coordinates of the intersection point are obtained

y=x/2+n
y=2x+7-n
x/2+n=2x+7-n
2n-7=3x/2
x=(4n-14)/3
y=(2n-7)/3+n=(5n-7)/3
If the intersection is in the second quadrant, then x = (4n-14) / 30
The solution is 7 / 5