As shown in the figure, ad is perpendicular to D, eg is perpendicular to g, angle e is equal to angle 3, and angle 1 is equal to angle 2

As shown in the figure, ad is perpendicular to D, eg is perpendicular to g, angle e is equal to angle 3, and angle 1 is equal to angle 2

And the picture

As shown in the figure, it is known that ad ⊥ BC, eg ⊥ BC, D and G are perpendicular feet respectively, ∠ GEC = ∠ 3

It is proved that: ∵ ad ⊥ BC, eg ⊥ BC, ∪ EGD = ∨ ADC = 90 °, eg ∥ ad, ∨ e = ∨ DAC, ∨ 3 = ∨ bad, and ∨ GEC = ∨ 3, ∨ bad = ∨ DAC, ∨ ad bisects ∨ BAC

In the triangle ABC, the angle BAC is 110 degrees. De is bisected vertically AB.FG The vertical bisection ac.e, G is the perpendicular foot. Find the degree of DAF
We need it now~

40 degrees
Connect DA and EA respectively
Because the vertical bisectors of AB and AC intersect BC at D and E,
So angle abd = angle DAB, angle EAC = angle ECA
And because the angle BAC is 110 degrees,
So angle DAB + angle ECA = 70 degrees
So angle abd + angle EAC = 70 degrees
So the angle DAE = 40 degrees
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