A wire is 22.4 meters long. It takes 14 meters for the first time and 12 meters for the second time. How many meters of wire are used in the two times? The formula is () A. 22.4×（14+12）B. 22.4×（1-14-12）C. 22.4÷（14+12）D. 22.4×14+12

A wire is 22.4 meters long. It takes 14 meters for the first time and 12 meters for the second time. How many meters of wire are used in the two times? The formula is () A. 22.4×（14+12）B. 22.4×（1-14-12）C. 22.4÷（14+12）D. 22.4×14+12

4 × 14 + 12

A wire is 8 meters long. The first time you use it, you need 12______ For the second time, it took 12 meters and there was still room left______ ．

8 × (1-12), = 8 × 12, = 4 (m); 4-12 = 312 (m); answer: there are still 4 meters left after the first use, and 312 meters left after the second use

There is a wire, the first time to use half less than 1 meter, the second time to use the remaining half more than 1 meter, the result is still 0.5 meters, then the original number of meters of this wire? The best equation

Suppose that the original length of the line is x meters, then 1 / 2x-1 is used for the first time. If the residual length of the second time is [1 / 2x-1] / 2 + 1, and the residual length is 0.5, then x - [1 / 2x-1] - [(1 / 2x-1) / 2 + 1] = 0.5, then x = 4 (meters)

Using a wire to install a lamp, half of it is less than one meter for the first time, and there are three meters left in the end. How long was the wire originally?

3 + 1 = 4 (m)
4 × 2 = 8 (m)

The first time a wire was used, half of it was less than 1 meter. The second time, the remaining half was more than 1 meter. Finally, there was 2.5 meters left. How long was the wire originally

13m

Using a wire to install a lamp, the first time you use half of it is less than one meter, the second time you use the remaining half of it is more than one meter, and there are still three meters left?

14

Use a wire to install a lamp. The first time you use half of it is less than one meter. The second time you use the remaining half and more than one meter. Finally you have 4.5 meters left

[X-(X/2)+1]-{[X-(X/2)+1]/2}-1=4.5
[X-(X/2)+1]/2=5.5
X-(X/2)+1=11
X/2=10,X=20m

One fourth of a meter was cut off for the first time, one sixth more than that for the second time, leaving three fifths of a meter?

1 / 4 + 1 / 4 ÷ (1 + 1 / 6) + 3 / 5 = 1 / 4 + 3 / 14 + 3 / 5 = 149 / 140 (m)

Two fifths of a wire is used for the first time, and 4.4m is used for the second time. The remaining wire is two fifths less than that used for the first time. Find the original length of the wire

The original length of the wire is x meters
（1-0.4）x-4.4=0.4x-0.4
The solution is x = 80
A: the original length of the wire was 80 meters

One wire is 35 meters long. Two fifths of the total length is used for the first time, and two fifths of the total length is used for the second time. How many meters of wire are left?

What's left: 35 × (1-2 / 5) - 2 / 5
=21-0.4
=20.6m