One wire takes 25% and another 60 meters, leaving one third. How many meters are left?

Total length = 60 ÷ (1-1 / 4-1 / 3) = 144m
144 × 1 / 3 = 48m
48 meters left

For the first time, a bundle of wires took more than half and three meters. For the second time, the remaining half was less than 10 meters. For the third time, it took 15 meters and there were still 25 meters left
Please calculate step by step!
But that's what I wrote, but I'm not right!

25+15=40 (40-10)*2=60 (60+3)*2=126
I wonder if the questioner can understand?

A wire is 5 / 6 meters long, 1 / 4 meters is used, how many meters are left

5/6-1/4
=10/12-3/12
=7/12

If you cut off two-thirds of a stick, there will be two meters left. How many meters is the length of the stick? If you cut off two-thirds of a stick, there will be several meters left

If 2 ÷ (1-2 / 3) = 6m, the original length of the wood is 6m
2-2 / 3 = 4 / 3M
If we cut off another 2 / 3 meters, there will be 4 / 3 meters left

For a bundle of wires, more than 3 meters of half of the total length were used for the first time, less than 10 meters of the remaining half were used for the second time, 15 meters were used for the third time, and finally 7 meters were left
How many meters was the wire?

（15-10+7+3-10-3×1/2）÷（1-1/2-1/2×1/2）
=13.5÷1/4
=54m

For the first time, more than 3 meters of the whole length of a bundle of wires were used. For the second time, less than 10 meters of the remaining half of the whole length were used. For the third time, 15 meters were used. Finally, 7 meters were left

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X is 108 meters long

For a 1-meter-long wire, cut off three fifths of the meter in the first time and the remaining three fifths in the second time. Which one is longer?

First time: 3 / 5m
The second time: (1-3 / 5) × 3 / 5 = 6 / 25m
3/5＞6/25
Answer the first truncated length

A 1 meter long wire, the first cut off three fifths of the meter, the second cut off the remaining three fifths, which cut off the longer? Find the formula!

First cut off three fifths of the meter = 3 / 5m
The second cut off the remaining three fifths = (1-3 / 5) * 3 / 5 = 6 / 25

For a wire, 1 / 3 of its total length was cut off for the first time, and 25% of its total length was cut off for the second time. There are still 20 meters left. How many meters is the total length of this wire?

Take the total length of this wire as unit 1, and cut it off twice, there is 1-1 / 3-25% = 5 / 12
Therefore, the total length of this wire: 20 △ 5 / 12 = 48 (m)
Equation solution:
The total length of this wire is x meters
（1-1/3-25%)x=20
5/12x=20
x=48

For a wire, 37.5% of the total length is used for the first time, and 27 meters is used for the second time. At this time, the length ratio of the used wire to the unused wire is 3:2?

27 (32 + 3-37.5%), = 27 (35-37.5%), = 27 (0.225), = 120 (m); a: the original length of this wire was 120 M

One wire takes 25% and another 60 meters, leaving one third. How many meters are left?