Cut a 1997 cm long wire into 199 cm and 177 cm long wires, and the rest is at least 100 cm long______ Cm

As shown in the table below, the length of 199 cm iron wire should be cut at least one, at most nine, the length of 177 cm iron wire should be cut at least one, at most ten, and the remaining part should be at least 6 cm. Answer: the remaining part should be at least 6 cm

Cut a 1997 cm long wire into 199 cm and 177 cm long wires, and the rest is at least 100 cm long______ Cm

For a piece of iron wire, 20% of the total length is used for the first time, and 15 meters is used for the second time. At this time, the ratio of the length used to the rest is exactly 4:1,
How long is the wire

Now it's full length
4÷（4＋1）＝80％
Wire length
15 (80% - 20%) = 25 (m)

There is a piece of iron wire. The first time you use half of it is more than 1 meter, and the second time you use the remaining 1 / 3 is less than 1 meter. At this time, there are still 15 meters left
How did the process come about

Backward method:
15-1 = 14m
14 ÷ (1-1 / 3) = 21m
21 + 1 = 22m
22 △ 1 / 2 = 44m
A: it was 44 meters long

For a wire, 20% of the total length is used for the first time, and 15 meters for the second time. This is exactly 25% of the remaining length. How long is the wire?

15÷【1/（1+25%）-20%】
=15÷【4/5-1/5】
=15÷3/5
=25m

For a piece of iron wire, one quarter of its total length is used for the first time, 30% for the second time, and 12 meters more than the first time. How many meters is the total length of the wire?

12÷（30%-1/4）
=12÷（0.3-0.25）
=12÷0.05
=240m
The wire is 240 meters long
Please click the [select as satisfactory answer] button below,

Xiao Ping finds three wires to do her homework. The length of the first wire is twice that of the second wire, the length of the third wire is six times that of the second wire, and how much of the length of the first wire is that of the third wire?

Let the length of the first wire be "1". 1 △ (1 × 2 × 6) = 1 △ 12 = 112. A: the length of the first wire is 112. 5 times that of the third wire

There are three wires, the length of the first one is 2 / 5 of the second one, which is 1.2 times of the second one, and the third one is 440cm longer than the second one
Now, form these three iron wires into small sections with equal length as possible. How many such sections can the first iron wire cut?

There are three iron wires, the length of the first one is 2 / 5 of the third one, which is 1.2 times of the second one, and the third one is 440cm longer than the second one
wrote it wrong
The second is 1 / 1.2 = 5 / 6 of the length of the first
So, the ratio of three lengths is
1：5/6：5/2=6：5：15
Because they can't be further divided, the minimum number of segments is 6 + 5 + 15 = 26
The length of each segment is 1 / 6 of the first one

The length of the three wires is 215 meters, the first one is 1 / 3, the second one is 3 / 4, and the third one is 2 / 5. The remaining lengths of the three wires are equal
How many meters are each of the three?

Let three lengths be x, y and Z respectively
Then 2 / 3x = 1 / 4Y = 3 / 5Z
x+y+z=215
Just solve the equation

There are three wires. The length of the first one is three fifths of the third one, which is 1.2 times of the second one. The third one is 440cm longer than the second one
There are three iron wires. The length of the first one is three fifths that of the third one, which is 1.2 times that of the second one. The third one is 440 cm longer than the second one. Now we need to cut these three iron wires into small sections as long as possible and of equal length. How many such small sections can the first iron wire cut?

Let the length of the first root be x, then the length of the second root is x / 1.2, and the length of the third root is (5 / 3) X. knowing that the length of the third root is 440 longer than the second root, we can get (5 / 3) x-x / 1.2 = 440, x = 528, the length of the first root is 528, and the length of the second root is 440, The third root is 880. Then get the greatest common divisor 88 of these three numbers. This greatest common divisor is the maximum length that can be divided. Then use the length 528 of the first root: the greatest common divisor to get the number of segments. The answer is 6

Cut a 1997 cm long wire into 199 cm and 177 cm long wires, and the rest is at least 100 cm long______ Cm