When the angle between the two forces is 90 degrees, what is the resultant force?

When the angle between the two forces is 90 degrees, what is the resultant force?

100N, composition of force, right triangle, one right side is 80N, one right side is 60N, hypotenuse is resultant force, 100N

If the wooden box on the horizontal plane moves in a straight line at a constant speed under the action of the horizontal force F1 = 60N to the East and the horizontal force F2 = 80N to the north, what is the friction force of the wooden box on the horizontal plane? In which direction does the object move

The resultant force of the horizontal East force F1 = 60N and the horizontal north Force F2 = 80N is f = √ F1 & # 178; + F2 & # 178; = 100N, the direction is east by North 53 & # 186; the object moves uniformly, the resultant force is 0, so the friction force F = f = 100N, the direction is opposite to the resultant force F, and the sliding friction force is opposite to the relative movement direction of the object, so the object moves in the direction of East by North 53 & # 186

An object starts to move on a smooth horizontal plane from rest under the action of horizontal constant force F1, TS is replaced by F2, and the object returns to the starting point after 2Ts. In this process, the ratio of F1 to F2 is ()
A. 12B. 13C. 45D. 43

Let the direction of the force at the beginning be positive, the acceleration be A1, and the acceleration in the next 2t0 be A2. From x = v0t + 12at2, we can get the displacement of the object in t0 time: x = 12a1t02 ① According to the velocity formula, v = a 1t 0 ② Displacement in the last 2t0 time: - x = V (2t0) + 12a2 (2t0) 2 ③ The formula of simultaneous ①, ② and ③ is: 12a1t02 = - (2a1t02 + 42a2t02); the solution is: A1A2 = 45, then f = ma is: F1F2 = A1A2 = 45, so C

A. The masses of two objects B are M1 and M2 respectively. They are stationary on a smooth horizontal plane. Now, the horizontal external force F is used to push object a, so that a and B can accelerate together, and the force of a on B can be calculated

Taking AB as a whole as the research object, we know f = (M1 + m2) a from Newton's second law, and get the acceleration a = f / (M1 + m2)
Taking B as the object of study, B is also the acceleration. According to Newton's law, the force on B is M2A = M2 × f / (M1 + m2)