An object with a mass of 1kg is subjected to two forces F1 = 3N and F2 = 4N respectively. If F1 and F2 are perpendicular to each other, then the acceleration of the object is A. 3 M / S ^ 2 b.4 M / S ^ 2 C.5 M / S ^ 2 d.7 M / S ^ 2

An object with a mass of 1kg is subjected to two forces F1 = 3N and F2 = 4N respectively. If F1 and F2 are perpendicular to each other, then the acceleration of the object is A. 3 M / S ^ 2 b.4 M / S ^ 2 C.5 M / S ^ 2 d.7 M / S ^ 2

Using the parallelogram rule, the resultant force of two forces is 5N a = f / M = 5N / 1kg = 5m / S ^ 2

As shown in the figure, a wooden block placed on a horizontal table is subjected to three forces in the horizontal direction, namely F1, F2 and friction. The wooden block is in a static state, where F1 = 10N and F2 = 4N
A. If the force F1 is removed, the resultant force of the block in the horizontal direction may be 2Nb. If the force F1 is removed, the resultant force of the block in the horizontal direction must be 0C. If the force F2 is removed, the resultant force of the block in the horizontal direction may be 2nd. If the force F2 is removed, the resultant force of the block in the horizontal direction must be 0

When the wood block is placed on the horizontal table, it is subjected to three forces in the horizontal direction, namely F1, F2 and friction force. The wood block is at rest. According to the equilibrium condition, the static friction force is f = F1-F2 = 10n-4n = 6N, then the maximum static friction force is greater than or equal to 6N

When a block is placed on a horizontal table, it is subjected to three forces, i.e. F 1, F 2 and friction
Where F1 = 100N, F2 = 40n, and the directions of the two forces are opposite. If the force F1 is removed, the resultant force and friction force on the block in the horizontal direction are ()
A100N,40N B40N,60N
C40N,0 D0,40N

The resultant force of F1 and F2 is f = F1-F2 = 60N
Under this force, the block is stationary, which means that the maximum static friction of the block is greater than 60N
When F1 is removed, the thrust on the block is 40n, which is less than the maximum static friction of the object,
So the block is still static, so the resultant force is 0n and the friction force is 40n

When a wooden block is placed on a horizontal table, it is subjected to three forces, namely F1, F2 and friction F. the wooden block is in a static state, F1 = 10N, F2 = 2n, and F1 is removed to get the result

Since the block is still, F1 + F2 + F = 0
Remove F1: regardless of the angle of F1 and F2, the resultant force F1 + F2 should be between 8N and 12n, so f > = 8N
When F1 is removed, only F2 = 2nf2
So the block is still static, the resultant force = 0, f = F2, the direction is opposite