The calculation formula of arc length is known. The radius of the center of the arc is 5.05 meters, the angle of the arc is 23 degrees, and the starting point to the end point of the arc is 2 meters

According to the calculation formula of arc length, the radius of arc center is r = 5.05m, the angle of arc is a = 23 degrees, and the starting point to the end point of arc is L = 2m. Find the arc length C? A = 2 * arc sin ((L / 2) / R) = 2 * arc sin ((2 / 2) / 5.05) = 22.84 degrees = 22.84 * pi / 180 = 0.39867, arc C = a * r = 0.39867 * 5.05 = 2.01

Given the start point, end point and radius of the arc, calculate the center coordinates
Start point (x1, Y1), end point (X2, Y2), radius r

Let the center of the circle (x, y), the starting point a (x1, Y1), the ending point B (X2, Y2), the linear equation of the chord be l, and the midpoint of the chord be c. then C ((x1 + x2) / 2, (Y1 + Y2) / 2), because the line L is perpendicular to the line where the chord center distance lies, the product of the slope of the line where the chord center distance lies and the slope of L is - 1. (y1-y2) / (x1-x2) = - [y - (Y1 + Y2) / 2] / [x - (x1 + x2)

CAD can't draw superior arc when drawing circular arc. The command used is start point, end point, radius. The radius input is negative value, and the result is always inferior arc (the direction is counterclockwise)
It used to be that you could draw superior arcs with short lines, but now you can't draw them. According to the example steps in the book, what you draw is still inferior arcs. Please give me some advice

When operating, reverse the order of starting point and end point

CAD known starting point angle radius, how to draw arc

Use the polyline command (pline), specify the starting point, enter "a" (ARC), enter "a" (angle), enter the required angle; enter the radius; confirm, OK!

The corresponding height ratio of two similar triangles is 2:3, and the sum of their circumference is 20,
If the area difference is 5, what are their respective areas?

If it's the sky question, the answers are 4 and 9. Because for high school, the area ratio of similar triangles is the square of the side length ratio, and the side length ratio is equal to the high ratio

If the area ratio of two similar triangles is 4:9, then the ratio of their corresponding bisectors is 4:9______ ．

∵ the area ratio of two similar triangles is 4:9, ∵ the similarity ratio of these two similar triangles is 2:3, ∵ the ratio of their corresponding angular bisectors is equal to the similarity ratio, ∵ the ratio of their corresponding angular bisectors is 2:3

If the ratio of the bisectors of the corresponding angles of two similar triangles is 1:9, then their perimeter ratio is?

If the ratio of angle bisectors of two similar triangles is 1:9, their perimeter ratio is 1:9

If the ratio of the bisectors of the corresponding angles of two similar triangles is 3:4, then the ratio of the circumference is (fill in the blanks)

3:4
If the ratio of the bisectors of the corresponding angles of two similar triangles is 3:4, the ratio of the circumference is 3:4

A circle with a radius of 4 has a triangle next to it. The 3-angle shape accounts for 25% of the circle. Find the area of the triangle

3.14 * 4 * 4 * 25% = 12.56 A: the area of triangle is 12.56

The side length, side center distance and area of the inscribed triangle in the circle with radius of 2cm

Side length of inscribed triangle = 2 √ 3 = 34641
Edge center distance = 1
Area = 34641 / 2x1x3 = 5196

The calculation formula of arc length is known. The radius of the center of the arc is 5.05 meters, the angle of the arc is 23 degrees, and the starting point to the end point of the arc is 2 meters