As shown in the figure, it is known that OD bisects BOC and OE bisects AOC, if BOC = 70 ° and AOC = 50 ° (1) Calculate the degree of AOB and its complement angle (2) Request the degree of ∠ doc and ∠ AOE, judge whether ∠ DOE and ∠ AOB are complementary, and explain the reason The DOA is a right angle, 90 degrees, and the diagram is drawn by myself

As shown in the figure, it is known that OD bisects BOC and OE bisects AOC, if BOC = 70 ° and AOC = 50 ° (1) Calculate the degree of AOB and its complement angle (2) Request the degree of ∠ doc and ∠ AOE, judge whether ∠ DOE and ∠ AOB are complementary, and explain the reason The DOA is a right angle, 90 degrees, and the diagram is drawn by myself

：（1）∠AOB=∠BOC+∠AOC=70°+50°=120°,
The complementary angle is 180 ° - AOB = 180 ° - 120 ° = 60 °;
（2）∠DOC=12×∠BOC=12×70°=35°
∠AOE=12×∠AOC=12×50°=25°．
The ∠ DOE is complementary to the ∠ AOB,
Reason: ∵ DOE = ∠ doc + ∠ COE = 35 ° + 25 ° = 60 °,
∴∠DOE+∠AOB=60°+120°=180°,
Therefore, DOE and AOB complement each other

(1) (2) if (1) AOB = α, other conditions remain unchanged, calculate the degree of EOF; (3) what rules can you find from (1) (2) results?

(1) AOC = 30 ° and AOC = 30, and the EOF = 30 ° and AOC, and the ? COE - ∠ (3) according to (1) (2), EOF = 12 ∠ AOB