It's very urgent. The parabola y = ax-3ax + 3 intersects the x-axis at a (- 1,0) B (4,0) intersects the y-axis at C The square of parabola y = ax - 3ax + 3 intersects X axis at a (- 1,0) B (4,0) intersects Y axis at C. 1. Find the analytical formula of parabola 2. Translate the parabola along the Y-axis and intersect the y-axis at point D. when BD = 2CD, find the coordinates of point D 3. If the parabola is folded along the straight line x = m, make the folded parabola intersecting straight line BC at two points P and Q, and P and Q are symmetrical about point C, draw the value graph of m by yourself. Because I don't have a picture

It's very urgent. The parabola y = ax-3ax + 3 intersects the x-axis at a (- 1,0) B (4,0) intersects the y-axis at C The square of parabola y = ax - 3ax + 3 intersects X axis at a (- 1,0) B (4,0) intersects Y axis at C. 1. Find the analytical formula of parabola 2. Translate the parabola along the Y-axis and intersect the y-axis at point D. when BD = 2CD, find the coordinates of point D 3. If the parabola is folded along the straight line x = m, make the folded parabola intersecting straight line BC at two points P and Q, and P and Q are symmetrical about point C, draw the value graph of m by yourself. Because I don't have a picture

Let the square of point D coordinate (0, t) BD = the square of 4CD; let the square of BD = the square of 16 + T; let the square of 4CD = (T-3) the square solution of T = 4 plus or minus 2 radical 21 / 3 T has two values; 3. Let P (E, f); then q (- E, 6-F) Note

Given the points a (0,5), P (x, y), and X + y = 8, the area of triangle AOP is 15, the coordinates of point P are obtained

P is on the line x + y = 8
AO=5
S=1/2*5*x=15
x=6
y=8-6=2
P(6,2)

As shown in the figure, P is a point on the image of the inverse scale function y = KX, the PA ⊥ X axis is at point a, and the area of △ Pao is 6. The following points also on the image of the inverse scale function are ()
A. （2，3）B. （-2，6）C. （2，6）D. （-2，3）

Since P is a point on the image of the inverse scale function y = KX, s = 12|k | = 6, and because the function is in the second quadrant, k = - 12. Then, substitute the coordinates in each option to judge: A, 2 × 3 = 6 ≠ - 12, so it is not on the function image; B, - 2 × 6 = - 12, so it is on the function image; C, 2 × 6 = 12 ≠ - 12, so it is not on the function image; D, (- 2) × 3 = - 6 ≠ - 12, so it is not on the function image So B

Given that the points P1 and P2 are on the image with inverse scale function y = 4 / X (x > 0), △ p1oa1 and △ p2a1a2 are isosceles right triangles, and the hypotenuse OA1 and A1A2 are on the x-axis
According to the above conditions, can you get the coordinates of A2?

Let A1 coordinate be (a, 0), A2 (B, 0), because △ p1oa1, △ p2a1a2 are isosceles right triangle, OA1, A1A2 are hypotenuse, so b > A, P1 coordinate is (A / 2,8 / a), P2 (a + B / 2,8 / B-A), and a / 2 = 8 / A, a + B / 2 = 8 / B-A, a = 4, B = 4 radical 2, so A2 coordinate is (4 radical 2,0)