It is known that the square of parabola y = ax + BX + C (a is less than 0) passes through point a (- 2,0), O (0,0) We know the square of parabola y = ax + BX + C (a)

Y = ax & # 178; + BX + C (A & lt; 0) goes through O (0,0) ‖ y = ax & # 178; + BX goes through the point a (- 2,0) 0 = 4a-2bb = 2A, a & lt; 0y = ax & # 178; + 2aX symmetry axis is x = - 1, and the closer x is to the symmetry axis, the larger y is
Similar to the figure below
The axis of symmetry is x = - 1
Contrast x = - 3, x = 3

The square of the parabola ax + BX + C passes through three points a (3,0) B (2, - 3) C (0, - 3)
(1) Find the analytic formula of parabola and whether there is a point P on the symmetry axis of the image (2) so that PA = Pb in the triangle. If there is, find out the coordinates of point P. if not, explain the reason

A parabola y = ax & # - 178; + BX + C passes through three points a (3,0) B (2, - 3) C (0, - 3), 1) find the analytic formula of parabola and the symmetry axis of image (2) whether there is a point P on the symmetry axis such that PA = Pb in the triangle. If there is, find out the coordinates of point P. if not, explain the reason. 1) substitute the coordinates of three points a, B, C into the parabola

Given that a (0,4), B (1, - 3), C (- 1, - 7) are on the parabola y = ax square + BX + C, then a-bc=
As long as the answer is urgent~

Answer: - 17

Given that the parabola y = AX2 + BX + C passes through the point (1,1), and the slope of the tangent at (2, - 1) is 1, find the values of a, B, C

Because y = AX2 + BX + C respectively passes through point (1,1) and point (2, - 1), so a + B + C = 1, ① 4A + 2B + C = - 1, ② y ′ = 2aX + B, so y ′| x = 2 = 4A + B = 1, ③ a = 3, B = - 11, C = 9 can be obtained from ①, ② and ③

It is known that the square of parabola y = ax + BX + C (a is less than 0) passes through point a (- 2,0), O (0,0) We know the square of parabola y = ax + BX + C (a)