There are two fixed points F1 (0, - 4) (0, - 4) in the plane, and the moving point satisfies the trajectory equation of mf1-mf2 absolute value = 8, M

There are two fixed points F1 (0, - 4) (0, - 4) in the plane, and the moving point satisfies the trajectory equation of mf1-mf2 absolute value = 8, M

If your topic is F1 (0,4), F2 (0, - 4), then | F1F2 | = 8, so the trajectory equation of M is:
X = 0, y is less than or equal to - 1 or Y is greater than or equal to 1
General conclusion | mf1-mf2 | = | F1F2 |, then M is the point between F1 and F2 on the straight line;
|MF1-MF2|=2a

The track of point m whose absolute value of the distance difference between two fixed points F1 (- 3,0) and F2 (3,0) is equal to 6 ()
A. Ellipse B. line segment C. hyperbola D. two rays

∵ F1 (- 3,0), F2 (3,0) | F1F2 | = 6, so the absolute value of the distance difference between two fixed points F1 (- 3,0), F2 (3,0) is equal to 6. The trajectory of point m is two rays with F1 (- 3,0), F2 (3,0) as the endpoints, so D is selected

If there are two fixed points F1 (0, - 5) and F2 (0,5) in the plane, then the trajectory equation of the point whose absolute value of the distance difference between the two fixed points on the plane is equal to 6 is?

F1F2 = 10 = 2cc = 52A = 6A = 3, then B & # 178; = C & # 178; - A & # 178; = 16, so x & # 178 / 9-y & # 178 / 16 = 1

Given two points F1 (negative 5,0) and F2 (5,0), find the point trajectory equation whose absolute value of distance difference is 6

According to the definition of hyperbola, a = 3, B = 4, the trajectory equation is x ^ 2 / 9-y ^ 2 / 16 = 25